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The effect of increasing temperature on the solubility of two
solids
Tim Conway
Marling School, Stroud, UK |
Aim
Question :
What is the effect of increasing temperature on the solubility
of
(a) a Salt
(b) a Sugar
when they are placed in
(1) Ethanol
(2) Water.
This is basically asking if solubility is proportional to the
temperature of the solvent. The idea is to do it in ethanol and
water with a salt and a sugar. This is to test the question in two
different liquids (solvents) with two different solids (solutes) to
reach a more accurate answer.
Predictions
Solubility is the number of grams of the solute that will
dissolve in 100 g of the solvent. Some things may dissolve in water
but not in other liquids and some things may dissolve in other
liquids and not in water.
Water is a polar solvent. Polar solvents are liquids whose
molecules display a permanent dipole. A dipole has two oppositely
charged poles (like a magnet). A molecule with a dipole is a
molecule with a positive and a negative end. Ionic compounds are
compounds that will split into two or more ions when placed in a
liquid. Ions are particles that are positively charged (cations) or
negatively charged (anions). Ionising liquids (polar liquids
capable of dissolving ionic compounds) will dissolve ionic
compounds well because they can pull both anions (with the positive
ends of the molecules) and cations off (with the negative ends of
its molecules). Salts are ionic compounds so I would expect them
both to dissolve well in water.
I am going to use sodium chloride (common or table salt) in my
experiment.
e.g.
| NaCl + polar liquid |
 |
Na+ + Cl-
(dissolved in polar liquid) |
| NaCl + H2O |
 |
Na+(aq) +
Cl-(aq) |
| Table Salt + Water |
 |
Sodium +
Chloride |
So when you heat a polar liquid (water) it should dissolve a
greater quantity than at room temperature (22-25 degrees C). The
liquid molecules have more energy to move around and break the
chemical bonds between the sodium and the chloride ions in the
compound. They do that by attracting an ion by the oppositely
charged end of the dipole in the molecule.
Because liquid molecules have more energy to break the chemical
bonds between component particles in compounds, I would expect most
compounds to dissolve better at high temperatures rather than low
temperatures.
Ethanol is an organic compound and therefore is likely to be a
covalent compound and unlikely to be a polar liquid. I do not
expect ethanol to dissolve ionic compounds such as sodium
chloride.
Most compounds should follow the general rule (a solute will
dissolve better when the solvent is at a higher temperature rather
than a low temperature). Sugars are not ionic compounds and
therefore do not have ionic bonds. Instead they have covalent
bonds. Covalent compounds may act differently to ionic compounds
and therefore, the liquid molecules may need more or less energy to
break the chemical bonds.
Equipment
| Goggles |
(to protect the eyes) |
| Tripods |
(these were needed to support the
gauzes and the beakers) |
| Gauzes |
(these were used to keep the beaker
steady and to spread the flame over a larger area under the
beaker) |
| Bunsen Burners |
(these were used for heating because
out of the heat sources available they are the most efficient and
also the easiest to use) |
| Thermometers |
(they were used to measure the
temperature) |
| Beakers |
(to contain the solvent) |
| Balance |
(to weigh out the solutes) |
| Mat |
(to protect the surface of the
bench) |
Unfortunately, due to time and other restrictions, I was not
able to use ethanol in my experiments. If ethanol had been used, a
water trough would have been needed because ethanol must not be
allowed to heat too rapidly and because of its low boiling point
(78°C). This is for safety, because ethanol can catch fire or
even explode.
Chemicals
| H2O |
(Water) |
| NaCl |
(Sodium chloride [Common or table
salt] ) |
|
C12H22O11 |
(Sucrose [sometimes called table
sugar] ) |
Method
Because I couldn’t use Ethanol, the question is now
:
What is the effect of increasing temperature on the solubility
of
(a) a Salt
(b) a Sugar
when they are placed in
(1) Water.

100 ml of water were placed in a beaker.

Solid was added in 5g lots at each temperature.

The solid was stirred in with a stirring rod. When all the 5g had
dissolved, another 5g was added. This carried on until there was
some solid in the bottom of the beaker that wouldn’t
dissolve.

The beaker was heated on a tripod over a Bunsen burner, until it
reached the right temperature. When that happened, solid was added
in 5g lots until there was some left that wouldn’t
dissolve.
If the temperature needed was lower than room temperature, the
beaker had to be cooled. This was done by placing it in the freezer
for a while (done at home).

When there was solid left on the bottom, which wouldn’t
dissolve, it meant the solution had become saturated (no more of
the solute could dissolve). When the solution had become saturated
at a particular temperature, the amount was recorded (correct to
5g) and another temperature was done. This made each result
accurate to 5g.
This process was repeated for both solutes
(sugar and salt) at 5, 25, 45, 65, 85 °C
This experiment was a fair test because
- There was a constant amount of water in each beaker.
- When the experiment was repeated, all the conditions were kept
the same.
Key factors which could influence the results were
- The amount of water in each beaker.
- The length of time each amount of solid was given to
dissolve.
(To save time in the next lesson, a beaker of sugar solution
was left in a beaker inside a sealed bag. A week later there were
organisms growing in it. They were white and filamentous. This
obviously had to be thrown away.)
Results
SALT
| Temperature
(°C) |
Solubility (g of solute per 100g of Solvent) |
|
Experiment
1 |
Experiment
2 |
Average |
| 5 |
30 |
30 |
30 |
| 25 |
30 |
30 |
30 |
| 45 |
30 |
30 |
30 |
| 65 |
30 |
30 |
30 |
| 85 |
30 |
30 |
30 |
The first results seemed odd, so they were repeated. The second
experiment produced identical results. Because it produced the same
results, it is likely that they are right and that the first
results were not anomalous.
SUGAR
It was necessary to do the experiment twice, to make sure that
the results were correct and not anomalous. When that had been
done, the average of the two results could be found. In this case,
because both results were the same, the average came out as the
same figure. Ideally, if there had been more time, it would have
been better to do the experiment three times. As these results came
out exactly the same, it is quite a good indicator that they are
accurate.
| Temperature
(°C) |
Solubility (g of solute per 100g of Solvent) |
|
Experiment
1 |
Experiment
2 |
Average |
| 5 |
10 |
10 |
10 |
| 25 |
45 |
45 |
45 |
| 45 |
95 |
95 |
95 |
| 65 |
125 |
125 |
125 |
| 85 |
195 |
195 |
195 |
(Click on the graph to see an
enlarged version of it.)
(Click on the graph to see an
enlarged version of it.)
(Click on the graph to see an
enlarged version of it.)
On these graphs. The best fit line was calculated by a
regression equation (y = a + bx), i.e.
Best fit line = Intercept + ( Slope * Temperature ).
Because of this the line can only be used to predict solubility
within the temperature range in the experiment. It should not be
used for predictions outside this range.
SALT
SUGAR
| Slope : |
2.25 |
| Intercept : |
-7.25 |
Conclusion
The results show that the solubility of sugar (sucrose) did
increase with temperature but the solubility of salt (sodium
chloride) stayed the same at all temperatures.
This simplified extract comes from page 161 in the book
‘Principles of Chemistry’:
If heat is given off when a particular substance is
dissolved in a solvent, then the solubility of that salt in that
solvent will decrease with increasing temperature. On the other
hand, if heat is absorbed when a particular substance is dissolved
in a solvent, then the solubility of that salt in that solvent will
increase with increasing temperature.
It then goes on to say that most salts’ solubility increases
with increasing temperature.
SALT
Sodium chloride doesn’t appear to fit into either category
because its solubility doesn’t decrease or increase with
increasing temperature.
I referred to two books (GCSE Chemistry Classbook and GCSE
Chemistry) to check my results. They both confirmed that sodium
chloride does keep a constant solubility with increasing
temperature. But, they both showed the solubility of salt at 35g.
These differed from my results of 30g. My results are probably
slightly inaccurate because of two reasons :
- Salt was added in 5g lots so the results were only accurate to
5g. This may mean that my results could have in fact been
32-4g.
- I used tap water which would have sodium ions and chloride ions
in. These may account for the last few grammes.
The effect of increasing temperature on the solubility of a salt
(Sodium Chloride [NaCl] )when placed in water (H2O) (g
solute/100g solvent) is nothing. There is no change of solubility
at any of the temperatures I have done. Because of this, it may
mean that Sodium Chloride is very strongly ionic and can be broken
down so easily by water. This would mean that the solution becomes
completely saturated straight away.
SUGAR
On page 163 of ‘Principles of Chemistry’ it says
:
An ionizing solvent such as water, will not dissolve
not only ionic substances but also substances of high polarity.
Because sugar dissolves in water, it means that a sugar compound is
a substance of high polarity.
The effect of increasing temperature on the solubility of a
sugar (Sucrose [C12H22O11] ) when
placed in water (H2O) is a change in solubility. If the
temperature is lowered the solubility gets less and if the
temperature is raised the solubility rises. This is because the
water molecules have more or less energy to move around and break
the chemical bonds. When there is more energy, the molecules can
break more of the bonds between the component particles in the
compound.
Improvements
- A water bath could have been used to heat the beakers in. This
would have allowed the contents to heat less rapidly.
- The solid could have been added in smaller amounts (e.g. 2g).
Or, the solid could have been added (in 5g lots) until the solution
was saturated and then the rest of the salt in the last lot could
be weighed. You could then take that amount away from 5g and it
would give you a more accurate saturation point.
- Using distilled water to cut out Na+ and
Cl- ions.
References
Dunstan, S. 1968. Principles of Chemistry. Van Nostrand
Reinhold
- Chapter 13 Solution, Solubility and Solvents.
- Pages 159-164
- Page 165 Table 13.3
McDuell, B. 1997. GCSE Chemistry Classbook. Letts
McDuell, B. 1997. GCSE Chemistry Study Guide. Letts
Computer programs used
Microsoft Encarta 97
Microsoft Excel Version 5.0
Microsoft Word
Paint Shop Pro
Encyclopaedia Britannica 97
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